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diff --git a/data/manhattan.npz b/data/manhattan.npz Binary files differnew file mode 100644 index 0000000..37808fb --- /dev/null +++ b/data/manhattan.npz diff --git a/docs/source/auto_examples/images/bak.png b/docs/source/auto_examples/images/bak.png Binary files differnew file mode 100644 index 0000000..25e7e8e --- /dev/null +++ b/docs/source/auto_examples/images/bak.png diff --git a/docs/source/auto_examples/images/sinkhorn.png b/docs/source/auto_examples/images/sinkhorn.png Binary files differnew file mode 100644 index 0000000..e003e13 --- /dev/null +++ b/docs/source/auto_examples/images/sinkhorn.png diff --git a/examples/plot_Intro_OT.py b/examples/plot_Intro_OT.py new file mode 100644 index 0000000..2e2c6fd --- /dev/null +++ b/examples/plot_Intro_OT.py @@ -0,0 +1,373 @@ +# coding: utf-8 +""" +============================================= +Introduction to Optimal Transport with Python +============================================= + +This example gives an introduction on how to use Optimal Transport in Python. + +""" + +# Author: Remi Flamary, Nicolas Courty, Aurelie Boisbunon +# +# License: MIT License +# sphinx_gallery_thumbnail_number = 1 + +############################################################################## +# POT Python Optimal Transport Toolbox +# ------------------------------------ +# +# POT installation +# ``````````````````` +# +# * Install with pip:: +# +# pip install pot +# * Install with conda:: +# +# conda install -c conda-forge pot +# +# Import the toolbox +# ``````````````````` +# + +import numpy as np # always need it +import pylab as pl # do the plots + +import ot # ot + +import time + +############################################################################## +# Getting help +# ````````````` +# +# Online documentation : `<https://pythonot.github.io/all.html>`_ +# +# Or inline help: +# + +help(ot.dist) + + +############################################################################## +# First OT Problem +# ---------------- +# +# We will solve the Bakery/Cafés problem of transporting croissants from a +# number of Bakeries to Cafés in a City (in this case Manhattan). We did a +# quick google map search in Manhattan for bakeries and Cafés: +# +# .. image:: images/bak.png +# :align: center +# :alt: bakery-cafe-manhattan +# :width: 600px +# :height: 280px +# +# We extracted from this search their positions and generated fictional +# production and sale number (that both sum to the same value). +# +# We have acess to the position of Bakeries ``bakery_pos`` and their +# respective production ``bakery_prod`` which describe the source +# distribution. The Cafés where the croissants are sold are defined also by +# their position ``cafe_pos`` and ``cafe_prod``, and describe the target +# distribution. For fun we also provide a +# map ``Imap`` that will illustrate the position of these shops in the city. +# +# +# Now we load the data +# +# + +data = np.load('../data/manhattan.npz') + +bakery_pos = data['bakery_pos'] +bakery_prod = data['bakery_prod'] +cafe_pos = data['cafe_pos'] +cafe_prod = data['cafe_prod'] +Imap = data['Imap'] + +print('Bakery production: {}'.format(bakery_prod)) +print('Cafe sale: {}'.format(cafe_prod)) +print('Total croissants : {}'.format(cafe_prod.sum())) + + +############################################################################## +# Plotting bakeries in the city +# ----------------------------- +# +# Next we plot the position of the bakeries and cafés on the map. The size of +# the circle is proportional to their production. +# + +pl.figure(1, (7, 6)) +pl.clf() +pl.imshow(Imap, interpolation='bilinear') # plot the map +pl.scatter(bakery_pos[:, 0], bakery_pos[:, 1], s=bakery_prod, c='r', ec='k', label='Bakeries') +pl.scatter(cafe_pos[:, 0], cafe_pos[:, 1], s=cafe_prod, c='b', ec='k', label='Cafés') +pl.legend() +pl.title('Manhattan Bakeries and Cafés') + + +############################################################################## +# Cost matrix +# ----------- +# +# +# We can now compute the cost matrix between the bakeries and the cafés, which +# will be the transport cost matrix. This can be done using the +# `ot.dist <https://pythonot.github.io/all.html#ot.dist>`_ function that +# defaults to squared Euclidean distance but can return other things such as +# cityblock (or Manhattan distance). +# + +C = ot.dist(bakery_pos, cafe_pos) + +labels = [str(i) for i in range(len(bakery_prod))] +f = pl.figure(2, (14, 7)) +pl.clf() +pl.subplot(121) +pl.imshow(Imap, interpolation='bilinear') # plot the map +for i in range(len(cafe_pos)): + pl.text(cafe_pos[i, 0], cafe_pos[i, 1], labels[i], color='b', + fontsize=14, fontweight='bold', ha='center', va='center') +for i in range(len(bakery_pos)): + pl.text(bakery_pos[i, 0], bakery_pos[i, 1], labels[i], color='r', + fontsize=14, fontweight='bold', ha='center', va='center') +pl.title('Manhattan Bakeries and Cafés') + +ax = pl.subplot(122) +im = pl.imshow(C, cmap="coolwarm") +pl.title('Cost matrix') +cbar = pl.colorbar(im, ax=ax, shrink=0.5, use_gridspec=True) +cbar.ax.set_ylabel("cost", rotation=-90, va="bottom") + +pl.xlabel('Cafés') +pl.ylabel('Bakeries') +pl.tight_layout() + + +############################################################################## +# The red cells in the matrix image show the bakeries and cafés that are +# further away, and thus more costly to transport from one to the other, while +# the blue ones show those that are very close to each other, with respect to +# the squared Euclidean distance. + + +############################################################################## +# Solving the OT problem with `ot.emd <https://pythonot.github.io/all.html#ot.emd>`_ +# ----------------------------------------------------------------------------------- + +start = time.time() +ot_emd = ot.emd(bakery_prod, cafe_prod, C) +time_emd = time.time() - start + +############################################################################## +# The function returns the transport matrix, which we can then visualize (next section). + +############################################################################## +# Transportation plan vizualization +# ````````````````````````````````` +# +# A good vizualization of the OT matrix in the 2D plane is to denote the +# transportation of mass between a Bakery and a Café by a line. This can easily +# be done with a double ``for`` loop. +# +# In order to make it more interpretable one can also use the ``alpha`` +# parameter of plot and set it to ``alpha=G[i,j]/G.max()``. + +# Plot the matrix and the map +f = pl.figure(3, (14, 7)) +pl.clf() +pl.subplot(121) +pl.imshow(Imap, interpolation='bilinear') # plot the map +for i in range(len(bakery_pos)): + for j in range(len(cafe_pos)): + pl.plot([bakery_pos[i, 0], cafe_pos[j, 0]], [bakery_pos[i, 1], cafe_pos[j, 1]], + '-k', lw=3. * ot_emd[i, j] / ot_emd.max()) +for i in range(len(cafe_pos)): + pl.text(cafe_pos[i, 0], cafe_pos[i, 1], labels[i], color='b', fontsize=14, + fontweight='bold', ha='center', va='center') +for i in range(len(bakery_pos)): + pl.text(bakery_pos[i, 0], bakery_pos[i, 1], labels[i], color='r', fontsize=14, + fontweight='bold', ha='center', va='center') +pl.title('Manhattan Bakeries and Cafés') + +ax = pl.subplot(122) +im = pl.imshow(ot_emd) +for i in range(len(bakery_prod)): + for j in range(len(cafe_prod)): + text = ax.text(j, i, '{0:g}'.format(ot_emd[i, j]), + ha="center", va="center", color="w") +pl.title('Transport matrix') + +pl.xlabel('Cafés') +pl.ylabel('Bakeries') +pl.tight_layout() + +############################################################################## +# The transport matrix gives the number of croissants that can be transported +# from each bakery to each café. We can see that the bakeries only need to +# transport croissants to one or two cafés, the transport matrix being very +# sparse. + +############################################################################## +# OT loss and dual variables +# -------------------------- +# +# The resulting wasserstein loss loss is of the form: +# +# .. math:: +# W=\sum_{i,j}\gamma_{i,j}C_{i,j} +# +# where :math:`\gamma` is the optimal transport matrix. +# + +W = np.sum(ot_emd * C) +print('Wasserstein loss (EMD) = {0:.2f}'.format(W)) + +############################################################################## +# Regularized OT with Sinkhorn +# ---------------------------- +# +# The Sinkhorn algorithm is very simple to code. You can implement it directly +# using the following pseudo-code +# +# .. image:: images/sinkhorn.png +# :align: center +# :alt: Sinkhorn algorithm +# :width: 440px +# :height: 240px +# +# In this algorithm, :math:`\oslash` corresponds to the element-wise division. +# +# An alternative is to use the POT toolbox with +# `ot.sinkhorn <https://pythonot.github.io/all.html#ot.sinkhorn>`_ +# +# Be careful of numerical problems. A good pre-processing for Sinkhorn is to +# divide the cost matrix ``C`` by its maximum value. + +############################################################################## +# Algorithm +# ````````` + +# Compute Sinkhorn transport matrix from algorithm +reg = 0.1 +K = np.exp(-C / C.max() / reg) +nit = 100 +u = np.ones((len(bakery_prod), )) +for i in range(1, nit): + v = cafe_prod / np.dot(K.T, u) + u = bakery_prod / (np.dot(K, v)) +ot_sink_algo = np.atleast_2d(u).T * (K * v.T) # Equivalent to np.dot(np.diag(u), np.dot(K, np.diag(v))) + +# Compute Sinkhorn transport matrix with POT +ot_sinkhorn = ot.sinkhorn(bakery_prod, cafe_prod, reg=reg, M=C / C.max()) + +# Difference between the 2 +print('Difference between algo and ot.sinkhorn = {0:.2g}'.format(np.sum(np.power(ot_sink_algo - ot_sinkhorn, 2)))) + +############################################################################## +# Plot the matrix and the map +# ``````````````````````````` + +print('Min. of Sinkhorn\'s transport matrix = {0:.2g}'.format(np.min(ot_sinkhorn))) + +f = pl.figure(4, (13, 6)) +pl.clf() +pl.subplot(121) +pl.imshow(Imap, interpolation='bilinear') # plot the map +for i in range(len(bakery_pos)): + for j in range(len(cafe_pos)): + pl.plot([bakery_pos[i, 0], cafe_pos[j, 0]], + [bakery_pos[i, 1], cafe_pos[j, 1]], + '-k', lw=3. * ot_sinkhorn[i, j] / ot_sinkhorn.max()) +for i in range(len(cafe_pos)): + pl.text(cafe_pos[i, 0], cafe_pos[i, 1], labels[i], color='b', + fontsize=14, fontweight='bold', ha='center', va='center') +for i in range(len(bakery_pos)): + pl.text(bakery_pos[i, 0], bakery_pos[i, 1], labels[i], color='r', + fontsize=14, fontweight='bold', ha='center', va='center') +pl.title('Manhattan Bakeries and Cafés') + +ax = pl.subplot(122) +im = pl.imshow(ot_sinkhorn) +for i in range(len(bakery_prod)): + for j in range(len(cafe_prod)): + text = ax.text(j, i, np.round(ot_sinkhorn[i, j], 1), + ha="center", va="center", color="w") +pl.title('Transport matrix') + +pl.xlabel('Cafés') +pl.ylabel('Bakeries') +pl.tight_layout() + + +############################################################################## +# We notice right away that the matrix is not sparse at all with Sinkhorn, +# each bakery delivering croissants to all 5 cafés with that solution. Also, +# this solution gives a transport with fractions, which does not make sense +# in the case of croissants. This was not the case with EMD. + +############################################################################## +# Varying the regularization parameter in Sinkhorn +# ```````````````````````````````````````````````` +# + +reg_parameter = np.logspace(-3, 0, 20) +W_sinkhorn_reg = np.zeros((len(reg_parameter), )) +time_sinkhorn_reg = np.zeros((len(reg_parameter), )) + +f = pl.figure(5, (14, 5)) +pl.clf() +max_ot = 100 # plot matrices with the same colorbar +for k in range(len(reg_parameter)): + start = time.time() + ot_sinkhorn = ot.sinkhorn(bakery_prod, cafe_prod, reg=reg_parameter[k], M=C / C.max()) + time_sinkhorn_reg[k] = time.time() - start + + if k % 4 == 0 and k > 0: # we only plot a few + ax = pl.subplot(1, 5, k / 4) + im = pl.imshow(ot_sinkhorn, vmin=0, vmax=max_ot) + pl.title('reg={0:.2g}'.format(reg_parameter[k])) + pl.xlabel('Cafés') + pl.ylabel('Bakeries') + + # Compute the Wasserstein loss for Sinkhorn, and compare with EMD + W_sinkhorn_reg[k] = np.sum(ot_sinkhorn * C) +pl.tight_layout() + + +############################################################################## +# This series of graph shows that the solution of Sinkhorn starts with something +# very similar to EMD (although not sparse) for very small values of the +# regularization parameter, and tends to a more uniform solution as the +# regularization parameter increases. +# + +############################################################################## +# Wasserstein loss and computational time +# ``````````````````````````````````````` +# + +# Plot the matrix and the map +f = pl.figure(6, (4, 4)) +pl.clf() +pl.title("Comparison between Sinkhorn and EMD") + +pl.plot(reg_parameter, W_sinkhorn_reg, 'o', label="Sinkhorn") +XLim = pl.xlim() +pl.plot(XLim, [W, W], '--k', label="EMD") +pl.legend() +pl.xlabel("reg") +pl.ylabel("Wasserstein loss") + +############################################################################## +# In this last graph, we show the impact of the regularization parameter on +# the Wasserstein loss. We can see that higher +# values of ``reg`` leads to a much higher Wasserstein loss. +# +# The Wasserstein loss of EMD is displayed for +# comparison. The Wasserstein loss of Sinkhorn can be a little lower than that +# of EMD for low values of ``reg``, but it quickly gets much higher. +# |